12c^2-5c-2=0

Solution for 12c^2-5c-2=0 equation:

Simplifying
12c2 + -5c + -2 = 0

Reorder the terms:
-2 + -5c + 12c2 = 0

Solving
-2 + -5c + 12c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-1 + -4c)(2 + -3c) = 0

Subproblem 1
Set the factor '(-1 + -4c)' equal to zero and attempt to solve:

Simplifying
-1 + -4c = 0

Solving
-1 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -4c = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -4c = 0 + 1
-4c = 0 + 1

Combine like terms: 0 + 1 = 1
-4c = 1

Divide each side by '-4'.
c = -0.25

Simplifying
c = -0.25
Subproblem 2
Set the factor '(2 + -3c)' equal to zero and attempt to solve:

Simplifying
2 + -3c = 0

Solving
2 + -3c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -3c = 0 + -2
-3c = 0 + -2

Combine like terms: 0 + -2 = -2
-3c = -2

Divide each side by '-3'.
c = 0.6666666667

Simplifying
c = 0.6666666667
Solution
c = {-0.25, 0.6666666667}